- #1

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So, the first thing I tried was just dividing the whole equation by [tex](y-yx^2)[/tex] and then factored out the y to get [tex]\frac{dy}{dx} = \frac{(y+1)^2}{y(1-x^2)}[/tex]. Next I expanded the numerator on the right side of the equation and then split them all into idividual fractions to get:

[tex]\frac{dy}{dx} = \frac{y}{1-x^2}+\frac{2}{1-x^2}+\frac{1}{y(1-x^2)}[/tex].

I just don't see how I can go from here?